last change: 2022-08-07
Transcendental Numbers
Just some notes.
Relation of Number Sets
The illustration works for both, β or β. Depending on the choice, πΈ is either the real algebraic numbers or the complex algebraic numbers, and likewise the same is true for π and π. Not affected by this choice is β, which is always the set of just the quotients of integers β€, which are also not affected.
β€: integer numbers
β: rational numbers, i.e. quotients
β: real numbers
β: complex numbers
πΈ: algebraic numbers
π := β\β (or β\β): irrational numbers (not a ring)
π := β\πΈ (or β\πΈ): transcendental numbers (not a ring)
Note that:
β β πΈ β β
π β π β β
πΈ and π intersect, but neither is a subset of the other.
There are numbers which are both irrational and algebraic, but some algebraic numbers are not irrational and some irrational numbers are not algebraic.
Examples:
β(2) β πΈ and β(2) β π (β(2) β π)
1 β πΈ, but 1 β π
Ο β π, but Ο β πΈ (Ο β π)
Lemma 0:
logba is irrational for a,b β β with a β b, b β 1.
Proof.
Let a, b be integers with a β b, b β 1. Then βi,j β β we have aβ± β bΚ² by the fundamental theorem of arithmetic.
And then
aβ± β bΚ²
β (aβ±)1/i β (bΚ²)1/i
β ai/i β bj/i
β aΒΉ β bj/i
β logba β logb(bj/i)
β logba β j/i (βi,j β β)
β βi,j β β: logba = j/i
β logba β β . β
Gelfond-Schneider Theorem
Theorem 1 (Gelfond-Schneider theorem):
If b β πΈβ{0,1}, p β πβ©πΈ, then bα΅ is transcendental.
Corollary 1.1a (Contrapositive A of the Gelfond-Schneider theorem):
If tα΅ is algebraic, p β πβ©πΈ, and t β {0,1}, then t is transcendental.
Proof.
Let tα΅ algebraic, p β πβ©πΈ, and t β {0,1}. Then tα΅ is not transcendental. With the contrapositive of theorem 1 it follows that t β πΈβ{0,1} or p β πβ©πΈ. Because we know that by the hypothesis p β πβ©πΈ, it follows that t β πΈβ{0,1}. We also know that t β {0,1}, so t β πΈβ{0,1} βͺ {0,1} β t β πΈ β t β π. β
Corollary 1.1b (Contrapositive B of the Gelfond-Schneider theorem):
If bα΅ is algebraic and b β πΈ\{0,1}, then p β πβ©πΈ.
Proof.
Let bα΅ algebraic and b β πΈβ{0,1}. Then bα΅ is not transcendental. With the contrapositive of theorem 1 it follows that b β πΈβ{0,1} or p β πβ©πΈ. Because we know by the hypotheis that b β πΈβ{0,1}, it follows that p β πβ©πΈ. β
Corollary 1.2:
logba is transcendental for a,b β β with a β b, b > 1.
Proof.
Let a,b β β with a β b, b > 1. Then blogba = a is algebraic. With blogba algebraic and algebraic b β {0,1} it follows with corollary 1.1b that logba β πβ©πΈ. For a proof by contradiction, assume logba β πΈ. From lemma 0 we know that logba β π. With logba β π, β πΈ it follows that logba β πβ©πΈ, which is a contradiction, because we already know that logba β πβ©πΈ, so the assumption is false and it follows that logba β πΈ β logba β π. β
Corollary 1.3:
e^Ο is transcendental, because
e^Ο
= e^(-Ο Β· -1)
= e^(-Ο Β· iΒ²)
= e^(iΟ Β· -i)
= (e^(iΟ))β»β±
= (-1)β»β±, which is transcendental by the Gelfond-Schneider theorem, because -1 is algebraic and -i is irrational.
Hermite-Lindemann Theorem (aka. Lindemann-WeierstraΓ Theorem)
Theorem 2 (Hermite-Lindemann theorem, aka. Lindemann-WeierstraΓ theorem):
if Ξ±β, ..., Ξ±β are algebraic numbers that are linearly independent over the rational numbers β, then eΞ±β, ..., eΞ±β are algebraically independent over β.
Corollary 2.1 (Corollary to the Hermite-Lindemann theorem):
If πΌ β πΈ\{0}, then eπΌ is transcendental.
Proof.
Let πΌ β πΈ\{0}. Then {πΌ} is a linearly independent set over the rationals. By the Hermite-Lindemann theorem, {eπΌ} is an algebraically independent set, or in other words eπΌ is transcendental. β
Corollary 2.2:
e is transcendental, because 1 is algebraic, so by corollary 2.1 eΒΉ is transcendental.
Corollary 2.3 (Contrapositive to corollary 2.1):
If eα΅ is algebraic and t β 0, then t is transcendental.
Proof:
Let t β 0 and for a proof by contradiction, assume that t is not transcendental, i.e. t is algebraic, then by corollary 2.1 eα΅ is transcendental. That's a contradiction, so the assumption cannot be true, i.e. t is transcendental. β
Corollary 2.4:
The natural logarithm of any algebraic number πΌ β {0, 1} is transcendental, because elog(πΌ) = πΌ is algebraic, so by corollary 2.3, the exponent is transcendental.
That means that all of log(2), log(3), log(4), log(5/7), and log(-7/45) are transcendental.